(2x^2-x-10)(2x-5)=0

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Solution for (2x^2-x-10)(2x-5)=0 equation: 


Simplifying
(2x2 + -1x + -10)(2x + -5) = 0

Reorder the terms:
(-10 + -1x + 2x2)(2x + -5) = 0

Reorder the terms:
(-10 + -1x + 2x2)(-5 + 2x) = 0

Multiply (-10 + -1x + 2x2) * (-5 + 2x)
(-10(-5 + 2x) + -1x * (-5 + 2x) + 2x2 * (-5 + 2x)) = 0
((-5 * -10 + 2x * -10) + -1x * (-5 + 2x) + 2x2 * (-5 + 2x)) = 0
((50 + -20x) + -1x * (-5 + 2x) + 2x2 * (-5 + 2x)) = 0
(50 + -20x + (-5 * -1x + 2x * -1x) + 2x2 * (-5 + 2x)) = 0
(50 + -20x + (5x + -2x2) + 2x2 * (-5 + 2x)) = 0
(50 + -20x + 5x + -2x2 + (-5 * 2x2 + 2x * 2x2)) = 0
(50 + -20x + 5x + -2x2 + (-10x2 + 4x3)) = 0

Combine like terms: -20x + 5x = -15x
(50 + -15x + -2x2 + -10x2 + 4x3) = 0

Combine like terms: -2x2 + -10x2 = -12x2
(50 + -15x + -12x2 + 4x3) = 0

Solving
50 + -15x + -12x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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